Guzzle을 사용하여 JSON으로 POST 요청을 보내려면 어떻게해야합니까?

Guzzle을 사용하여 JSON으로 POST 요청을 보내려면 어떻게해야합니까?

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누구든지 postJSON을 사용 하는 올바른 방법을 알고 Guzzle있습니까?

$request = $this->client->post(self::URL_REGISTER,array(
                'content-type' => 'application/json'
        ),array(json_encode($_POST)));

나는 얻을 internal server error서버에서 응답을. Chrome을 사용하여 작동합니다 Postman.

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들어 목구멍 5 & 6 당신은 이런 식으로 할 :

use GuzzleHttp\Client;

$client = new Client();

$response = $client->post('url', [
    GuzzleHttp\RequestOptions::JSON => ['foo' => 'bar']
]);

문서

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들면 폭식 <= 4 :

원시 게시물 요청이므로 JSON을 본문에 넣으면 문제가 해결되었습니다.

$request = $this->client->post($url,array(
                'content-type' => 'application/json'
        ),array());
$request->setBody($data); #set body!
$response = $request->send();

return $response;

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간단하고 기본적인 방법 (guzzle6) :

$client = new Client([
    'headers' => [ 'Content-Type' => 'application/json' ]
]);

$response = $client->post('http://api.com/CheckItOutNow',
    ['body' => json_encode(
        [
            'hello' => 'World'
        ]
    )]
);

응답 상태 코드와 본문 내용을 얻으려면 다음과 같이하십시오.

echo '<pre>' . var_export($response->getStatusCode(), true) . '</pre>';
echo '<pre>' . var_export($response->getBody()->getContents(), true) . '</pre>';

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이것은 나를 위해 일했다 (Guzzle 6 사용)

$client = new Client(); 
$result = $client->post('http://api.example.com', [
            'json' => [
                'value_1' => 'number1',
                'Value_group' =>  
                             array("value_2" => "number2",
                                    "value_3" => "number3")
                    ]
                ]);

echo($result->getBody()->getContents());

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$client = new \GuzzleHttp\Client();

$body['grant_type'] = "client_credentials";
$body['client_id'] = $this->client_id;
$body['client_secret'] = $this->client_secret;

$res = $client->post($url, [ 'body' => json_encode($body) ]);

$code = $res->getStatusCode();
$result = $res->json();

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이것은 Guzzle 6.2에서 작동합니다.

$gClient =  new \GuzzleHttp\Client(['base_uri' => 'www.foo.bar']);
$res = $gClient->post('ws/endpoint',
                            array(
                                'headers'=>array('Content-Type'=>'application/json'),
                                'json'=>array('someData'=>'xxxxx','moreData'=>'zzzzzzz')
                                )
                    );

문서 guzzle에 따르면 json_encode를 수행하십시오.

---

$client = new \GuzzleHttp\Client(['base_uri' => 'http://example.com/api']);

$response = $client->post('/save', [
    'json' => [
        'name' => 'John Doe'
    ]
]);

return $response->getBody();

---

use GuzzleHttp\Client;

$client = new Client();

$response = $client->post('url', [
    'json' => ['foo' => 'bar']
]);

문서를 참조하십시오 .

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@ user3379466의 답변은 $data다음과 같이 설정하여 작동하도록 할 수 있습니다 .

$data = "{'some_key' : 'some_value'}";

What our project needed was to insert a variable into an array inside the json string, which I did as follows (in case this helps anyone):

$data = "{\"collection\" : [$existing_variable]}";

So with $existing_variable being, say, 90210, you get:

echo $data;
//{"collection" : [90210]}

Also worth noting is that you might want to also set the 'Accept' => 'application/json' as well in case the endpoint you're hitting cares about that kind of thing.

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@user3379466 is correct, but here I rewrite in full:

-package that you need:

 "require": {
    "php"  : ">=5.3.9",
    "guzzlehttp/guzzle": "^3.8"
},

-php code (Digest is a type so pick different type if you need to, i have to include api server for authentication in this paragraph, some does not need to authenticate. If you use json you will need to replace any text 'xml' with 'json' and the data below should be a json string too):

$client = new Client('https://api.yourbaseapiserver.com/incidents.xml', array('version' => 'v1.3', 'request.options' => array('headers' => array('Accept' => 'application/vnd.yourbaseapiserver.v1.1+xml', 'Content-Type' => 'text/xml'), 'auth' => array('username@gmail.com', 'password', 'Digest'),)));

$url          = "https://api.yourbaseapiserver.com/incidents.xml";
        
$data = '<incident>
<name>Incident Title2a</name>
<priority>Medium</priority>
<requester><email>dsss@mail.ca</email></requester>
<description>description2a</description>
</incident>';

    $request = $client->post($url, array('content-type' => 'application/xml',));

    $request->setBody($data); #set body! this is body of request object and not a body field in the header section so don't be confused.

    $response = $request->send(); #you must do send() method!
    echo $response->getBody(); #you should see the response body from the server on success
    die;

--- Solution for * Guzzle 6 * --- -package that you need:

 "require": {
    "php"  : ">=5.5.0",
    "guzzlehttp/guzzle": "~6.0"
},

$client = new Client([
                             // Base URI is used with relative requests
                             'base_uri' => 'https://api.compay.com/',
                             // You can set any number of default request options.
                             'timeout'  => 3.0,
                             'auth'     => array('you@gmail.ca', 'dsfddfdfpassword', 'Digest'),
                             'headers' => array('Accept'        => 'application/vnd.comay.v1.1+xml',
                                                'Content-Type'  => 'text/xml'),
                         ]);

$url = "https://api.compay.com/cases.xml";
    $data string variable is defined same as above.


    // Provide the body as a string.
    $r = $client->request('POST', $url, [
        'body' => $data
    ]);

    echo $r->getBody();
    die;

---

Above answers did not worked for me somehow. But this works fine for me.

 $client = new Client('' . $appUrl['scheme'] . '://' . $appUrl['host'] . '' . $appUrl['path']);

 $request = $client->post($base_url, array('content-type' => 'application/json'), json_encode($appUrl['query']));

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Simply use this it will work

   $auth = base64_encode('user:'.config('mailchimp.api_key'));
    //API URL
    $urll = "https://".config('mailchimp.data_center').".api.mailchimp.com/3.0/batches";
    //API authentication Header
    $headers = array(
        'Accept'     => 'application/json',
        'Authorization' => 'Basic '.$auth
    );
    $client = new Client();
    $req_Memeber = new Request('POST', $urll, $headers, $userlist);
    // promise
    $promise = $client->sendAsync($req_Memeber)->then(function ($res){
            echo "Synched";
        });
      $promise->wait();

참고URL : https://stackoverflow.com/questions/22244738/how-can-i-use-guzzle-to-send-a-post-request-in-json