스트림을 사용하여 BigDecimals 추가

스트림을 사용하여 BigDecimals 추가

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LinkedList함께 추가하려는 BigDecimals (이 예제에서는 ) 모음이 있습니다. 이를 위해 스트림을 사용할 수 있습니까?

Stream수업에 몇 가지 방법이 있다는 것을 알았습니다.

Stream::mapToInt
Stream::mapToDouble
Stream::mapToLong

각각 편리한 sum()방법이 있습니다. 우리가 알다시피하지만, float및 double연산은 거의 항상 나쁜 생각이다.

BigDecimals를 요약하는 편리한 방법이 있습니까?

이것은 지금까지 가지고있는 코드입니다.

public static void main(String[] args) {
    LinkedList<BigDecimal> values = new LinkedList<>();
    values.add(BigDecimal.valueOf(.1));
    values.add(BigDecimal.valueOf(1.1));
    values.add(BigDecimal.valueOf(2.1));
    values.add(BigDecimal.valueOf(.1));

    // Classical Java approach
    BigDecimal sum = BigDecimal.ZERO;
    for(BigDecimal value : values) {
        System.out.println(value);
        sum = sum.add(value);
    }
    System.out.println("Sum = " + sum);

    // Java 8 approach
    values.forEach((value) -> System.out.println(value));
    System.out.println("Sum = " + values.stream().mapToDouble(BigDecimal::doubleValue).sum());
    System.out.println(values.stream().mapToDouble(BigDecimal::doubleValue).summaryStatistics().toString());
}

보시다시피, 나는을 사용하여 BigDecimal을 요약하고 BigDecimal::doubleValue()있지만 이것은 예상대로 정확하지 않습니다.

후손에 대한 답변 후 수정 :

두 답변 모두 매우 도움이되었습니다. 나는 약간을 추가하고 싶었다 : 나의 실제 시나리오는 raw 컬렉션을 포함하지 않으며 BigDecimal, 그것들은 송장에 싸여있다. 그러나 map()스트림 기능을 사용하여 Aman Agnihotri의 대답을 설명하기 위해 Aman Agnihotri의 답변을 수정할 수있었습니다 .

public static void main(String[] args) {

    LinkedList<Invoice> invoices = new LinkedList<>();
    invoices.add(new Invoice("C1", "I-001", BigDecimal.valueOf(.1), BigDecimal.valueOf(10)));
    invoices.add(new Invoice("C2", "I-002", BigDecimal.valueOf(.7), BigDecimal.valueOf(13)));
    invoices.add(new Invoice("C3", "I-003", BigDecimal.valueOf(2.3), BigDecimal.valueOf(8)));
    invoices.add(new Invoice("C4", "I-004", BigDecimal.valueOf(1.2), BigDecimal.valueOf(7)));

    // Classical Java approach
    BigDecimal sum = BigDecimal.ZERO;
    for(Invoice invoice : invoices) {
        BigDecimal total = invoice.unit_price.multiply(invoice.quantity);
        System.out.println(total);
        sum = sum.add(total);
    }
    System.out.println("Sum = " + sum);

    // Java 8 approach
    invoices.forEach((invoice) -> System.out.println(invoice.total()));
    System.out.println("Sum = " + invoices.stream().map((x) -> x.total()).reduce((x, y) -> x.add(y)).get());
}

static class Invoice {
    String company;
    String invoice_number;
    BigDecimal unit_price;
    BigDecimal quantity;

    public Invoice() {
        unit_price = BigDecimal.ZERO;
        quantity = BigDecimal.ZERO;
    }

    public Invoice(String company, String invoice_number, BigDecimal unit_price, BigDecimal quantity) {
        this.company = company;
        this.invoice_number = invoice_number;
        this.unit_price = unit_price;
        this.quantity = quantity;
    }

    public BigDecimal total() {
        return unit_price.multiply(quantity);
    }

    public void setUnit_price(BigDecimal unit_price) {
        this.unit_price = unit_price;
    }

    public void setQuantity(BigDecimal quantity) {
        this.quantity = quantity;
    }

    public void setInvoice_number(String invoice_number) {
        this.invoice_number = invoice_number;
    }

    public void setCompany(String company) {
        this.company = company;
    }

    public BigDecimal getUnit_price() {
        return unit_price;
    }

    public BigDecimal getQuantity() {
        return quantity;
    }

    public String getInvoice_number() {
        return invoice_number;
    }

    public String getCompany() {
        return company;
    }
}

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원래 답변

예, 가능합니다 :

List<BigDecimal> bdList = new ArrayList<>();
//populate list
BigDecimal result = bdList.stream()
        .reduce(BigDecimal.ZERO, BigDecimal::add);

그것이하는 일은 :

1. 를 얻습니다 List<BigDecimal>.
2. 그것을 Stream<BigDecimal>

3. reduce 메소드를 호출하십시오.

   3.1. 우리는 덧셈에 대한 아이덴티티 값을 제공합니다 BigDecimal.ZERO.

   3.2. 메소드 참조를 통해 BinaryOperator<BigDecimal>2를 더하는를 지정합니다 .BigDecimalBigDecimal::add

편집 후 업데이트 된 답변

새 데이터를 추가 했으므로 새 답변은 다음과 같습니다.

List<Invoice> invoiceList = new ArrayList<>();
//populate
Function<Invoice, BigDecimal> totalMapper = invoice -> invoice.getUnit_price().multiply(invoice.getQuantity());
BigDecimal result = invoiceList.stream()
        .map(totalMapper)
        .reduce(BigDecimal.ZERO, BigDecimal::add);

It is mostly the same, except that I have added a totalMapper variable, that has a function from Invoice to BigDecimal and returns the total price of that invoice.

Then I obtain a Stream<Invoice>, map it to a Stream<BigDecimal> and then reduce it to a BigDecimal.

Now, from an OOP design point I would advice you to also actually use the total() method, which you have already defined, then it even becomes easier:

List<Invoice> invoiceList = new ArrayList<>();
//populate
BigDecimal result = invoiceList.stream()
        .map(Invoice::total)
        .reduce(BigDecimal.ZERO, BigDecimal::add);

Here we directly use the method reference in the map method.

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This post already has a checked answer, but the answer doesn't filter for null values. The correct answer should prevent null values by using the Object::nonNull function as a predicate.

BigDecimal result = invoiceList.stream()
    .map(Invoice::total)
    .filter(Objects::nonNull)
    .filter(i -> (i.getUnit_price() != null) && (i.getQuantity != null))
    .reduce(BigDecimal.ZERO, BigDecimal::add);

This prevents null values from attempting to be summed as we reduce.

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Use this approach to sum the list of BigDecimal:

List<BigDecimal> values = ... // List of BigDecimal objects
BigDecimal sum = values.stream().reduce((x, y) -> x.add(y)).get();

This approach maps each BigDecimal as a BigDecimal only and reduces them by summing them, which is then returned using the get() method.

Here's another simple way to do the same summing:

List<BigDecimal> values = ... // List of BigDecimal objects
BigDecimal sum = values.stream().reduce(BigDecimal::add).get();

Update

If I were to write the class and lambda expression in the edited question, I would have written it as follows:

import java.math.BigDecimal;
import java.util.LinkedList;

public class Demo
{
  public static void main(String[] args)
  {
    LinkedList<Invoice> invoices = new LinkedList<>();
    invoices.add(new Invoice("C1", "I-001", BigDecimal.valueOf(.1), BigDecimal.valueOf(10)));
    invoices.add(new Invoice("C2", "I-002", BigDecimal.valueOf(.7), BigDecimal.valueOf(13)));
    invoices.add(new Invoice("C3", "I-003", BigDecimal.valueOf(2.3), BigDecimal.valueOf(8)));
    invoices.add(new Invoice("C4", "I-004", BigDecimal.valueOf(1.2), BigDecimal.valueOf(7)));

    // Java 8 approach, using Method Reference for mapping purposes.
    invoices.stream().map(Invoice::total).forEach(System.out::println);
    System.out.println("Sum = " + invoices.stream().map(Invoice::total).reduce((x, y) -> x.add(y)).get());
  }

  // This is just my style of writing classes. Yours can differ.
  static class Invoice
  {
    private String company;
    private String number;
    private BigDecimal unitPrice;
    private BigDecimal quantity;

    public Invoice()
    {
      unitPrice = quantity = BigDecimal.ZERO;
    }

    public Invoice(String company, String number, BigDecimal unitPrice, BigDecimal quantity)
    {
      setCompany(company);
      setNumber(number);
      setUnitPrice(unitPrice);
      setQuantity(quantity);
    }

    public BigDecimal total()
    {
      return unitPrice.multiply(quantity);
    }

    public String getCompany()
    {
      return company;
    }

    public void setCompany(String company)
    {
      this.company = company;
    }

    public String getNumber()
    {
      return number;
    }

    public void setNumber(String number)
    {
      this.number = number;
    }

    public BigDecimal getUnitPrice()
    {
      return unitPrice;
    }

    public void setUnitPrice(BigDecimal unitPrice)
    {
      this.unitPrice = unitPrice;
    }

    public BigDecimal getQuantity()
    {
      return quantity;
    }

    public void setQuantity(BigDecimal quantity)
    {
      this.quantity = quantity;
    }
  }
}

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You can sum up the values of a BigDecimal stream using a reusable Collector named summingUp:

BigDecimal sum = bigDecimalStream.collect(summingUp());

The Collector can be implemented like this:

public static Collector<BigDecimal, ?, BigDecimal> summingUp() {
    return Collectors.reducing(BigDecimal.ZERO, BigDecimal::add);
}

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If you don't mind a third party dependency, there is a class named Collectors2 in Eclipse Collections which contains methods returning Collectors for summing and summarizing BigDecimal and BigInteger. These methods take a Function as a parameter so you can extract a BigDecimal or BigInteger value from an object.

List<BigDecimal> list = mList(
        BigDecimal.valueOf(0.1),
        BigDecimal.valueOf(1.1),
        BigDecimal.valueOf(2.1),
        BigDecimal.valueOf(0.1));

BigDecimal sum =
        list.stream().collect(Collectors2.summingBigDecimal(e -> e));
Assert.assertEquals(BigDecimal.valueOf(3.4), sum);

BigDecimalSummaryStatistics statistics =
        list.stream().collect(Collectors2.summarizingBigDecimal(e -> e));
Assert.assertEquals(BigDecimal.valueOf(3.4), statistics.getSum());
Assert.assertEquals(BigDecimal.valueOf(0.1), statistics.getMin());
Assert.assertEquals(BigDecimal.valueOf(2.1), statistics.getMax());
Assert.assertEquals(BigDecimal.valueOf(0.85), statistics.getAverage());

Note: I am a committer for Eclipse Collections.

참고URL : https://stackoverflow.com/questions/22635945/adding-up-bigdecimals-using-streams